physics
posted by john .
Water is flowing down through the pipe shown in the drawing. Point A is 0.410 m higher than B. The speed of the water at A and B are vA = 5.00 m/s and vB = 3.80 m/s. Determine the difference PB  PA in pressures between B and A. The density of water is 1.00x10^3 kg/m3.

using the formula :P+rho*g*h + 1/2*rho*v^2=0
calculate: PA= 16518
PB = 7220
PBPA=7220(16518)=9298
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