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Algebra 1

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Janella has only quarters dimes and pennies in her pocket thee are eight coins in all and their total value is 83 cents how many of each type of coins does Janella have?

  • Algebra 1 -

    number of quarters= x
    number of dimes = y
    number of pennies =8-x-y

    value:
    25x + 10y + 1(8-x-y) = 83
    24x+ 9y = 75
    9y = 75 - 24x
    3y = 25 - 8x
    25 -8x must be a positive multiple of 3
    so clearly x can only be 1 , 2, or 3
    of those only x = 2 will work

    if x = 2
    3y = 25-16 = 9
    y = 3

    number of quarter = 2
    number of dimes = 3
    number of pennies = 8-2-3 = 3

    check: does she have 8 coins ? YES
    what is the value of those 8 coins?
    2(25) + 3(1) + 3(1) = 83 , YEAHHHH

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