chemistry

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given 10.8 grams of substance y,if the substance absorbs 231 kilojoules of energy and the specfic heat of substance is 6.55 J/g*0C what is the heat change

  • chemistry -

    q = mass x specific heat x delta T
    q = 231
    mass = 10.8
    sp.h. = 6.55
    dT= solve

  • chemistry -

    3.265 deg. C

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