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Train A leaves a station traveling at 80km/h. Two hours later, train B leaves the same direction at 90km/h. How long does it take train B to catch up to train A?

  • algebra -

    They will have traveled the same distance, but the difference is their times will be 2 hours

    time for slower train = D/80
    time for faster train = D/90

    D/80 - D/90 = 2
    times 720
    9D - 8D = 1440
    D = 1440
    Time for train B (the faster) = 1440/90 = 16 hrs.

    in 16 hrs, the faster train goes 16(90) = 1440
    in 18 hrs, the slower train goes 18(80) = 1440

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