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Calculus II

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A cable that weighs 1.5 lb/ft is used to lift 700 lb of coal up a mineshaft that is 400 ft deep. Find the work done.

  • Calculus II -

    Consider the cable as a whole lot of little cable bits, each of which must be lifted a different distance. The bits at the top only have to be lifted a little way, the bits near the bottom have to be lifted a long way.

    The 700 lb load has to go all the way up.

    Each little piece of length dx weighs 1.5 dx and has to be lifted a distance of x feet.

    The work done to lift each bit is its weight * the distance lifted. So, the whole job done is

    ∫[0,400] 1.5x + 700 dx

    multiply the lot by a conversion factor if you want Newtons instead of ft-lbs.

  • Calculus II -

    Wow this problem is easier than I thought it was. Thanks.

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