What is an equation for a direct variation whose graph passes through the point (–5, 3)?
Nevermind, I got it! ^.^
To find the equation for a direct variation, we can use the form y = kx, where k is the constant of variation. To determine the value of k, we can substitute the given point (–5, 3) into the equation:
3 = k × (-5)
Simplifying this equation:
3 = -5k
To solve for k, divide both sides of the equation by -5:
k = -3/5
Therefore, the equation for the direct variation is y = (-3/5)x.
To find the equation of a direct variation, we need to know the constant of variation, often denoted by k, and the coordinates of a point on the graph.
In this case, we are given that the graph passes through the point (-5, 3). Let's use this information to find the constant of variation.
In a direct variation, the equation takes the form y = kx, where y represents the dependent variable, x represents the independent variable, and k is the constant of variation.
Using the coordinates of the point (-5, 3), we can substitute the values into the equation and solve for k:
3 = k(-5)
Now, divide both sides of the equation by -5 to isolate k:
k = 3 / -5
Simplifying the fraction gives us:
k = -3/5
Thus, the equation of the direct variation is: y = (-3/5)x.