Calculate the mass of NaOH pellets required to prepare 1litre of 0.1Litre NaOH
1 L of 0.1L? What kind of double talk is that? You must have means 1 L of 0.1M NaOH.
mols NaOH needed = M x L = 0.1M x 1L = 0.1 mol NaOH.
mols NaoH = grams/molar mass. You know molar mass and mols, solve for grams.
4 gm
To calculate the mass of NaOH pellets required to prepare 1 liter of a 0.1 molar (M) solution of NaOH, you would need to follow these steps:
1. Determine the molar mass of NaOH. Na has an atomic mass of 23 grams/mol, O has an atomic mass of 16 grams/mol, and H has an atomic mass of 1 gram/mol. Adding them together, the molar mass of NaOH is 23 + 16 + 1 = 40 grams/mol.
2. Convert the desired molarity (0.1 M) into moles per liter. Molarity is defined as the number of moles of solute per liter of solution. Therefore, 0.1 M means there are 0.1 moles of NaOH in 1 liter of solution.
3. Use the molar mass of NaOH to convert moles into grams. Multiply the number of moles (0.1) by the molar mass (40 grams/mol) to get the mass required. The calculation would be Mass = Moles * Molar Mass, so Mass = 0.1 * 40 = 4 grams.
Therefore, you would need 4 grams of NaOH pellets to prepare 1 liter of a 0.1 M NaOH solution.