# Physics

posted by .

A ball rolling down a hill was displaced at 19.6m while uniformly accelerating from rest. If the final velocity was 5.00 m/s what was the rate of acceptation?

• Physics -

a = (V^2-Vo^2)/2d
a = (5^2-0)/39.2 = 0.6378 m/s^2.

## Similar Questions

1. ### Physics

Which of the following contains the most mechanical energy?
2. ### physics

a plane travels 5.0 x 10^2 while being accelerated uniformly from rest at the rate of 5.0 m/s. what final velocity does it attain?
3. ### physics

a ball rolling down a hill uniformly accelerated at 4 m/s2. assumong that it start from rest, what is its speed at the end of each of the first 3 s?
4. ### physics

A skier is accelerating down a 30.0° hill at a = 4.10 m/s2 a) What is the vertical component of her acceleration?
5. ### physics

A skier is accelerating down a 30.0 degrees hill at 1.80m/s^2. How long will it take her to reach the bottom of the hill, assuming she starts from rest and accelerates uniformly, if the elevation change is 375 m?
6. ### physics

A skier is accelerating down a 30.0° hill at a = 3.70 m/s2 ( (a) What is the vertical component of her acceleration?
7. ### physics

A ball starts at the origin from rest rolling down a hill. It takes seven seconds for the ball to reach point “A”, which is 25 meters from the origin. At point “B”, the ball’s velocity is 15 m/s. You may assume constant acceleration. …