problem solving  math
posted by confused .
3 persons are to divide among themselves 21 equal cask, of which 7 are full, 7 are half full, and 7 are empty. how can an equitable division be made, without pouring the wine from any cask into any other, in such a way that each person receives the same amount of wine and the same total number of casks? is there more than one way to accomplish this division

there are 7(1+1/2) = 21/2 casks of wine
Each person must thus get 7/2 = 3 1/2 casks
So, give 3 full and 1 half casks to two people, leaving
1 full and 5 half casks (3 1/2) for the 3rd person
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