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find the second derivative

f(x)= 1/(4u^2-3)^2

  • Calc -

    f(u) = (4u^2-3)^-2
    f' = -2(4u^2-3)(8u)
    = -16u(4u^2-3)^-3
    f" = -16(4u^2-3)^-2 + 48u(8u)(4u^2-3)^-4
    = 16(20u^2+3)(4u^2-3)^-4

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