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Math

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Find three consecutive integers such that nine less than three times the third is seven more than the sum of the first and second.

  • Math -

    ahh...those algebra days...
    so, anyways, here's what u do...

    1) identify the variables:

    Let the 1st integer be "x"
    Let the 2nd integer be "(x+1)"
    Let the 3rd integer be "(x+2)"

    2) now, set up the equation...

    3(x+2) - 9 = x + (x+1)

    3) SOLVE away!!! :D

    3x + 6 - 9 = 2x + 1

    3x - 3 = 2x + 1

    x = 4

    4) NOW the three consecutive integers will be...

    { 4, 5, 6, }
    --------
    YAY, the answer :D
    now, DON'T FORGET TO HERP THE DERP!!!

  • Math -

    solve as above, but don't forget the "seven more..."

    3(x+2) - 9 = x + (x+1) + 7

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