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A mixture of NaCl and NaBr has a mass of 2.04g and is found to contain 0.70g of Na. What is the mass of NaBr in the mixture?

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    A problem with two unknowns and two equations. Solve simultaneously.

    Let x = mass NaCl
    and y = mass NaBr
    -------------------
    x + y = 2.04
    x(atomic mass Na/molar mass NaCl) + y(atomic mass Na/molar mass NaBr) = 0.70
    ----------------------------------
    Substitute the numbers to get this.
    x + y = 2.04
    x*(23/58.4) + y*(23/102.9) = 0.70
    ------------------------
    Solve these two equations. You want y for mass NaBr. Post your work if you get stuck.

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