Dma 040

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Lenth of a rectangle is 7ft longer than twice the width. If the rooms perimeter is 158ft, whay are the rooms dimensions?
Width
Length

  • Dma 040 -

    Represent the unknowns with variables:
    Let x = width
    Let 2x + 7 = length (according to the first statement)
    Then we set up the equation. To set up, we need to recall that the perimeter of a rectangle is given by
    P = 2L + 2W
    where L is length and W is width.
    We know that P = 158. Substituting,
    158 = 2(2x + 7) + 2x
    We solve for x:
    158 = 4x + 14 + 2x
    158 - 14 = 6x
    144 = 6x
    x = 144/6
    x = 24 ft (width)
    2x+7 = 55 ft (length)

    hope this helps~ :3

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