algebra

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Susie purchased a laptop computer for $2000 at the beginning of the year in 2008,the value of the computer decreased by 20% each year. Susie wants to purchase a new laptop computer when the value of hers falls below $500. When will Susie be able to purchase a new laptop?

  • algebra -

    so you are solving

    2000(.8)^n = 500
    .8^n = 500/2000 = .25
    take log of both sides

    log .8^n = log .25
    n log .8 = log .25
    n = log .25/log .8 = appr 6.2 years

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