Microwave ovens emit microwave energy with a wavelength of 12.5 cm. What is the energy of exactly one photon of this microwave radiation?
1.5891x10^-24
E = hc/wavelength
Remember to change cm to m for wavelength.
To determine the energy of one photon of microwave radiation, you can use the equation:
Energy (E) = Planck's constant (h) × Speed of light (c) / wavelength (λ)
The value of Planck's constant is approximately 6.626 x 10^-34 joule · seconds (J·s) and the speed of light is approximately 3.00 x 10^8 meters per second (m/s).
First, convert the wavelength from centimeters to meters:
12.5 cm = 12.5 × 10^-2 meters = 0.125 meters
Now, plug the values into the equation:
E = (6.626 x 10^-34 J·s) × (3.00 x 10^8 m/s) / 0.125 m
Calculating this expression will give you the energy of one photon of microwave radiation in joules.
To calculate the energy of a photon, we can use the equation:
Energy = Planck's constant (h) × Speed of light (c) / Wavelength
Planck's constant (h) = 6.626 × 10^(-34) J·s
Speed of light (c) = 3 × 10^8 m/s
First, convert the wavelength from centimeters to meters:
12.5 cm = 12.5 × 10^(-2) m = 0.125 m
Now we can calculate the energy of one photon:
Energy = (6.626 × 10^(-34) J·s) × (3 × 10^8 m/s) / (0.125 m)
Energy = 1.59408 × 10^(-23) J
Therefore, the energy of one photon of microwave radiation with a wavelength of 12.5 cm is approximately 1.59408 × 10^(-23) Joules.