Calculus
posted by Tim .
I hate these
Y= (Square root of x)  2
________________________
(square root of x) + 2
Calculate dy/dx
Please help, thank you

y = (√x  2)/(√x + 2)
by the quotient rule
dy/dx = [ (x^(1/2) + 2)( (1/2)x^(1/2)  (x^(1/2) 2)((1/2)x^(1/2) ] / (√x+2)^2
= (1/2)x^(1/2) [ x^(1/2 + 2  x^(1/2) + 2]/(√x+2)^2
= (1/2)(1/√x)(4)/(√x+2)^2
= 2/(√x(√x+2)^2 )