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Find the Taylor series of f(x) = sin(x) at a = Pi/3.

  • Calculus -

    sin(x-π/3) = sin(π/3) + 1/1! cos(π/3)(x-π/3) - 1/2! sin(π/3)(x-π/3)^2 ...
    = √3/2 + 1/2 (x-π/3) - √3/4 (x-π/3)^2 ...

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