Calculus
posted by Bryan .
Find the Taylor series of f(x) = sin(x) at a = Pi/3.

sin(xπ/3) = sin(π/3) + 1/1! cos(π/3)(xπ/3)  1/2! sin(π/3)(xπ/3)^2 ...
= √3/2 + 1/2 (xπ/3)  √3/4 (xπ/3)^2 ...
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