Give an appropriate answer.
Let lim x→6 f(x)=81. Find lim x→6 4^√f(x).
that would be 4^√81 = 4^9
Was there some reason you didn't just plug in 81 for f(x)?
4^9 = 262144 Is this the answer!!
I got 3.
So, how did you get 3? Maybe I can show where you went wrong.
Ah. I see where I misread your question. You apparently meant "4^√" to mean 4th root (∜).
In that case, the answer is indeed 3.
My fault. Sorry about that. Thank you
Also suppose If lim x→6 had been lim x→5 would that had been changed the answer. Or it would be same.
To find the limit of 4^√f(x) as x approaches 6, we first need to determine the value of f(x) as x approaches 6. Given that lim x→6 f(x) = 81, it means that as x gets closer and closer to 6, the value of f(x) approaches 81.
Now, to find the limit of 4^√f(x) as x approaches 6, we substitute the value of f(x) into the expression. Since f(x) approaches 81 as x approaches 6, we have:
lim x→6 4^√f(x) = 4^√(lim x→6 f(x))
= 4^√81
= 4^9
= 262,144
Therefore, the limit of 4^√f(x) as x approaches 6 is 262,144.