Questions LLC
Login
or
Sign Up
Ask a New Question
Science
Physics
A proton with speed v perpendicular to a magnetic field B is experiencing a force F.If the speed of the proton is doubled,the new force is (a)F/2(b)F(c)2F(d)4F
1 answer
since F = qv x B,
2v -> 2F
You can
ask a new question
or
answer this question
.
Related Questions
There are two situations in which it possible for a charged particle to be in a magnetic field but not experiencing a magnetic
The magnetic field of the Earth at a certain location is directed vertically downward and has a magnitude of 54.0 µT. A proton
A proton is traveling at 2.3E6 m/s in a circular path in 0.75 T magnetic field. What is the magnitude of the force of the
A current I = 16 A is directed along the positive x-axis and perpendicular to a magnetic field. A magnetic force per unit length
A proton traveling due east in a region that contains only a magnetic field experiences a vertically upward force away from the
A proton moves perpendicular to a uniform magnetic field B at 1.20 107 m/s and experiences an acceleration of 2.00 1013 m/s2 in
A proton is moving in a circular orbit of radius 11.8 cm in a uniform magnetic field of magnitude 0.232 T directed perpendicular
A proton experiences a force of 4 Newton when it enters perpendicular to the direction of the magnetic field with a speed 100
A proton experiences a force of 4 Newton when it enters perpendicular to the direction of the magnetic field with a speed 100
A proton experiences a force of 4 Newton when it enters perpendicular to the direction of the magnetic field with a speed 100