Physics
posted by Cam .
A jetliner, travelling northward, is landing with a speed of 79 m/s. Once the jet touches down, it has 710 m of runway in which to reduce its speed to 7.4 m/s. Compute the the average accelaration (magnitude and direction) of the plane during landing.

v^2=u^2+2fs or f=(v^2u^2)/2s
=(7.4^279^2)/(2*710)
=(54.766241)/1420=4.36m/s^2
Negative acceleration (i.e. against the direction of motion)of 4.36m/s^2
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