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while at the shooting range, jonathan shoots a bullet traveling horizontally with speed of 35 m/s. the bullet hits a board, perpendicular to the surface, passes through it and emerges on the other side with speed of 21 m/s. if the board is 4.00cm thick, how long does the bullet take to pass through the board?

  • Physics -

    a = (V^2-Vo^2)/2d
    a = (21^2-35^2/0.08 = -9800 m/s^2.

    V = Vo + a*t = 21 m/s.
    35 + -9800t = 21
    t = 0.001429 s. = 1.429 ms.

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