geometry
posted by luis .
Given: FG (SEG) bisects BT (SEG)
BO=7x6
OT=5x+10
Prove: BO=50

I think we need to see the figure, but looking at the given, I think the point FG bisects and intersects BT at point O. Therefore we can say the lengths of segments BO and OT are equal, or
7x  6 = 5x + 10
7x  5x = 10 + 6
2x = 16
x = 8
Susbtituting,
BO = 7x  6
BO = 7(8)  6
BO = 56  6
BO = 50
Hope this helps~ :3
Respond to this Question
Similar Questions

geometry
We are learning about proofs. We drew lines between noncollinear points. Our table showed 2 points >> 1 line segment, 3 point >> 3 line segments, 4 points >> 6 line segments, 5 points >> 10 line seg, 6 points … 
Geometry
Given: ray AD bisects <BAC <DAC=3x, and <BAD=5x24 Prove: x=12 its a proof and i need help 
Geometry Please Help
Given: QS bisects ∠RQT; ∠R ≅ ∠ T Prove: SQ bisects ∠RST 
Geometry Please Help
Given: QS bisects ∠RQT; ∠R ≅ ∠ T Prove: SQ bisects ∠RST /Users/szeringue/Documents/triangle.doc 
GEOMETRY
GIVEN: TRIANGLE ABC,AD bisects <BAC,and AE=ED, PROVE:AE/AC=BD/BC 
Geometry
Given: angle BAC is congruent to angle ACD, segment BD bisects segment AC, and segment AC bisects angle BCD. Prove: quadrilateral ABCD is a rhombus. 
Math (Geometry)
Given: ABCD is arhombus. prove:AC bisects angle BAD and angel BCD. 
geometry
Given: FG (SEG) bisects BT (SEG) BO=7x6 OT=5x+10 Prove: BO=50 
geometry
Given: ABC,/ AD bisects <BAC, and /AE=/ED Prove: AE/AC = BD/BC 
Math
We are learning about proofs. We drew lines between noncollinear points. Our table showed 2 points >> 1 line segment, 3 point >> 3 line segments, 4 points >> 6 line segments, 5 points >> 10 line seg, 6 points …