# physics

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A rifle that shoots bullets at 404 m/s is to be aimed at a target 49.7 m away. If the center of the target is level with the rifle, how high (in cm) above the target must the rifle barrel be pointed so that the bullet hits dead center?

• physics -

The range is
R = v^2 sin2θ / g

so,
404^2 sin2θ /9.8 = 49.7
sin2θ = 9.8*49.7/404^2 = .00298
θ = 0.085°

not much of an elevation

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