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A rifle that shoots bullets at 404 m/s is to be aimed at a target 49.7 m away. If the center of the target is level with the rifle, how high (in cm) above the target must the rifle barrel be pointed so that the bullet hits dead center?

  • physics -

    The range is
    R = v^2 sin2θ / g

    so,
    404^2 sin2θ /9.8 = 49.7
    sin2θ = 9.8*49.7/404^2 = .00298
    θ = 0.085°

    not much of an elevation

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