pre calcalus
posted by sara .
(x+4)^2/3=9

pre calcalus 
Jai
(x+4)^(2/3) = 9
To do this, we raise both side by 3/2, so that the exponent 2/3 of the term on the left side will be cancelled:
(x + 4)^(2/3 * 3/2) = 9^(3/2)
(x + 4)^(1) = 3^3
x + 4 = 27
x = 27  4
x = 23
To check, substitute the x value to the original equation:
(23 + 4)^(2/3) = 9
27^(2/3) = 9
3^2 = 9
9 = 9
Thus x is indeed equal to 23.
Hope this helps~ :3
Respond to this Question
Similar Questions

Need some ideas.... for a PreK class
I am teaching a PreK class this summer and the theme for the next two weeks is Community History. What could I all my prek class to do that connects to this theme? 
prealgebra
kk my teach told me to describe and draw things that are about prealgebra and she told me to write what prealgebra is... so can anyone help me? 
pre calcalus
angle measure to degree form 401degrees 39minutes 24seconds 
pre calcalus
a circle with 4 inch radius, find length of arc when intercepted by central angle of 240 degrees 
pre calcalus
a 10 inch radius lawn roller makes 1.2 revolutionsper second,what is angular speed in radians per second 
pre calcalus
evaluate sec(1.7 
pre calcalus
evaluate sin(5pi/9) 
Calcalus
A population P is a function of time t that had 5000 when t=0 can be written P(t)= 5000+B(t)D(t). B(t) is the number of births since t=0 and D(t0 is the number of deaths since t=0. suppose at a given instant B=800 and dB/dt=100, and … 
Calcalus
If ln(x^215y)=xy+5 and y(4) by implicit differentation = Thus the equation of the tangent line to the graph at point (4,1) is y= 
Calcalus
Solve the equations below exactly Give your answers in radians, and find all possible values for t If there is more than one answer, enter your solutions in a comma separated list (a) sin(t)= sqroot(2)/2 when t= (b) cos(t)=1/2 when …