physics
posted by john .
Coasting due east on your bicycle at 8.0 m/s, you encounter a sandy patch of road 7.4 m across. When you leave the sandy patch your speed has been reduced to 5.5 m/s. Assuming the bicycle slows with constant acceleration, what was its acceleration in the sandy patch? Give both magnitude and direction

physics 
Henry
a = (V^2Vo^2)/2d
a = (5.5^28^2)/14.8 = 2.28 m/s^2.
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