posted by Anonymous .
Solve for x.
-3x^2 = -12
x^2 = 4
x = ±2
thanks and what about this one ?
Simplify the expression
I'm getting confused because of the negative exponent
anything^0 = 1, so we just have
(3x^-1y^2)^3 = 27 x^-3 y^6 = 27y^6/x^3
negative exponents indicate a swap between numerator and denominator
x^-3 = 1/x^3
1/x^-3 = x^3
recall that x^a/x^b = x^(a-b)