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If an electron travels 0.150 m from an electron gun to a TV screen in 19.0 ns, what voltage was used to accelerate it? (Note that the voltage you obtain here is lower than actually used in TVs to avoid the necessity of relativistic corrections.)

  • physics -

    s=at²/2
    a=2s/t²
    F=ma
    eU =Fs =mas =m2s²/t²
    U= 2ms²/et² =
    =2•9.1•10⁻³¹•(0.15)²/1.6•10⁻¹⁹•(19•10⁻⁹)²=
    =709 V

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