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A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.2 m/s. The car is a distance d away. The bear is 26 m behind the tourist and running at 6.0 m/s. The tourist reaches the car safely. What is the maximum possible value for d?

  • physics -

    d2 = d1 + 26 m.
    r2*t = r1*t + 26
    6t = 4.2t + 26
    1.8t = 26
    t = 14.44 s.

    d = d1 = 4.2*14.44 = 60.67 m..

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