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Algebra2

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The perimeter of a square is 12 cm greater than that of another square. It's area exceeds the area of the other by 39 cm^2. Find the perimeter of each square.

  • Algebra2 -

    4a = 4b+12
    a^2 = b^2+39
    (b+3)^2 = b^2+39
    b^2+6b+9 = b^2+39
    6b=30
    b=5
    so, a=8

    check:
    4*8 = 32 = 4*5+12
    8^2 = 64 = 5^2+39

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