Quantum physics
posted by SS01 .
docs(dot)google(dot)com/file/d/0B4uUFmATOigqbjAxU2tRNjVwa1E/edit?usp=sharing
(a) What is the inner product of the 3rd row and 14th row of this matrix?
b) What is the inner product of the 3rd row with itself?
C) Suppose we have a quantum circuit that takes the input 0> and outputs +>, and also takes the input 1> and outputs −−>. If we input √2*i/√3+> + 1/√3−>, what does the circuit output?

Any luck with the rest of the questions?

yup, i got few questions, like 2 , 6 ,7 ,8
what about you? 
anybody please help

Got 7 and 8 for the moment!
can you help with the rest? 
ya.....but i need more question's answers to get 80%

getstudyroom(dot)com/course/43483#

what about answers?

somebody please answer this question....

for c part i think the answer is 1/(sqrt3)for 0) and ((sqrt2)*i)/(sqrt3) for 1) ... i am not sure

did anyone check with the above answer?

nope......no chance left any luck for 9 or 12?

help needed even for q.4 ...anyone?

1 ques ans pls..

can anyone tell me wats the ans of prob 2?

any clue for 12, is it all 8?

im missing 5 and 12 ..

i tell you 5 and 12 you tell me 9

Help for Q. No 6

i need 5 9 and 12 rest i will help

6 then I will help with 5, 9 and 12

Leave it.. Its not good to discuss exam questions outside. I don't know how i reached here.. i just realized i don't need course certificate, if I'm not worth it. So, I will try to solve it myself. You do too.. :)

C) 1/sqrt(3)0> + (sqrt(2)*i)/sqrt(3)1>

SS01: The answer to 12 is only 2.
I need 4 and 9.. can you give me the answers now? 
For question 9 the answer is
CNOT12, CNOT23
Please give us the answer to question 4 and 6!
Thank you! 
4a 0
4b 1
12 2 
110/36
can anyone tell me wats the ans of 2 nd 5?please 
my ans C) 1/sqrt(3)0> + (sqrt(2)*i)/sqrt(3)1> is showing wrong..last attempt left..please help me

How to do Number 6?

what is the answer of 11

how to find the state of the composite system in prob 2?? please ans

ank, The answer to question 5 is
1/(sqrt(3))
in the first box and
(2*i)/sqrt(6)
in the second box. 
rare, for q2  just multiply the two quibits states.
Answer to q2:
1/sqrt(2)*3/5 > 00>
(3*i)/(5*sqrt(2)) > 01>
4/(5*sqrt(2)) > 10>
(4*i)/(5*sqrt(2)) > 11>
Please, give us answers to question 6! Thanks 
thanks..ans6 its 1 and 1/2

thanks..6a1,6b1/2

Thank you ppl!

Please help for 3,8 and 11

anoy, answer for 8 is
8(a)
1/sqrt(2) 00>
0 01>
0 10>
1/sqrt(2) 11>
8(b)
0 00>
1/sqrt(2) 01>
1/sqrt(2) 10>
0 11>
8(c)
1/2 00>
1/2 01>
1/2 10>
1/2 11> 
answer for Q3 is option 4
answer for Q11 is option 2
Please revert..........with thanks
and let me know if any help needed 
thanks for help but Q3 and Q11 are false

any help for Q 3 and 11
I am not sure what to tick.......
sorry anoy.....it was just a assumption. 
what is the answer of 3?

Whats the solution of Question 1???

1) 10/36 some help for Q3?

any1 got the ans to q 10?

Someone know answers for 7th and 10th? Attempts are finishing :(

Someone give me Q3 and I give him/her all the others questions!

Anon: 3rd choice foê Q3

Anon, please help with 7 and 10

7)A) I,H
7)B) X,H 
ANS TO 3 IS c
WATS Q10? 
@Anon, ans to question #10 is 1110
Can someone tell me the ans to question 5? 
@ Lord
The circuit is a phase change (Z) with a Hadamard (H); plug in the eqn (simple arithmetic if u understand the material)
TY for ans tho, wish i knew how u arrived to it, i wrote out all the y's and i couldn't figure out s 
Q11 answer please......

What is the superposition that results if you apply the Hadamard transform H⊗n to the state 12√(0n⟩+1n⟩)? (Here, 0n⟩:=00⋯0n⟩ and 1n⟩:=11⋯1n⟩.)

answer of q 3. is 3rd option

answer of q 2 is
3/(5*sqrt(2)) 00>
(3*i)/(5*sqrt(2)) 01>
4/(5*sqrt(2)) 10>
(4*i)/(5*sqrt(2)) 11> 
answer 0f question 11 is option no. 4 and it is correct one, sure.