Upon decomposition, one sample of magnesium fluoride produced 1.65kg of magnesium and 2.58kg of fluorine. A second sample produced 1.38kg of magnesium.
How much fluorine (in grams) did the second sample produce?
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To find out how much fluorine the second sample produced, we need to use the information given about the first sample and make a comparison.
In the first sample, we know that 1.65kg of magnesium produced 2.58kg of fluorine. We can use this information to calculate the ratio of magnesium to fluorine.
Ratio of magnesium to fluorine in the first sample:
= 1.65kg magnesium / 2.58kg fluorine
Now we can use this ratio to find the amount of fluorine produced by the second sample.
Amount of fluorine in the second sample:
= Ratio of magnesium to fluorine x Amount of magnesium in the second sample
Given that the amount of magnesium in the second sample is 1.38kg, we can substitute this value into the equation:
Amount of fluorine in the second sample:
= (1.65kg magnesium / 2.58kg fluorine) x 1.38kg magnesium
Now we can calculate this value to obtain the amount of fluorine produced by the second sample:
Amount of fluorine in the second sample:
= (1.65kg/2.58kg) x 1.38kg
= 0.6395 x 1.38kg
= 0.88281kg
Since we need the amount of fluorine in grams, we can convert this to grams by multiplying by 1000:
Amount of fluorine in the second sample = 0.88281kg x 1000g/kg
= 882.81g
Therefore, the second sample produced 882.81 grams of fluorine.