what potential energy is acquired by a block of steel whose mass is 50 kg when it is raised 200 cm?

PE = mg*h = 50*9.8*2m = 980 Joules

Well, let's calculate the potential energy, but I must warn you, my jokes will be iron-clad.

So, we know that potential energy (PE) is given by the formula PE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height.

Given that the mass is 50 kg, the height is 200 cm (or 2 meters, if we're being serious), and the acceleration due to gravity is approximately 9.8 m/s², let's do some calculations, shall we?

PE = (50 kg) × (9.8 m/s²) × (2 m)
PE = 980 Joules

Voilà! The potential energy of the block of steel is 980 Joules! Now, that's a lot of potential for some seriously funny business.

To calculate the potential energy acquired by a block of steel when it is raised, we can use the formula:

Potential Energy = (mass) × (gravity) × (height)

Given:
Mass of the block (m) = 50 kg
Height (h) = 200 cm = 2 meters (since 1 meter = 100 cm)
Acceleration due to gravity (g) = 9.8 m/s²

Plug in the values into the formula:

Potential Energy = 50 kg × 9.8 m/s² × 2 meters
= 980 Joules

Therefore, the block of steel acquires a potential energy of 980 Joules when it is raised 200 cm.

To determine the potential energy acquired by the block of steel, we need to recall the formula for gravitational potential energy:

Potential Energy = mass x acceleration due to gravity x height

The mass of the block is given as 50 kg, and the height it is raised is 200 cm. However, it would be better to convert the height to meters for consistency. There are 100 centimeters in a meter, so 200 cm is equal to 2 meters.

Now we can calculate the potential energy acquired by the block:

Potential Energy = 50 kg x 9.8 m/s^2 x 2 m

Firstly, we multiply the mass (50 kg) by the acceleration due to gravity (9.8 m/s^2). Then, we multiply the result by the height (2 m).

Potential Energy = 980 Joules

Therefore, the block of steel acquires 980 Joules of potential energy when it is raised 200 cm.