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A die is thrown twice. Find the probability that the number obtained in the first throw is smaller than that in the second throw.

  • maths -

    just add them up, considering the 1st throw:

    6: 0
    5: 1/6
    4: 2/6
    ...
    1: 5/6
    sum: (1/6)(15/6) = 5/12
    since the chance of throwing each of the 1st numbers is 1/6.

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