maths
posted by satyajeet .
if 3 cot theta =4 find the value of 5cos theta2sintheta/5cos theta+3sin theta

3 cot ( theta ) = 4 Divide both sides by 3
cot ( theta ) = 4 / 3
sin ( theta ) = + OR  1 / sqrt [ 1 + cot ( teta ) ^ 2 ]
In this case :
sin ( theta ) = + OR  1 / sqrt [ 1 + ( 4 / 3 ) ^ 2 ]
sin ( theta ) = + OR  1 / sqrt ( 1 + 16 / 9 )
sin ( theta ) = + OR  1 / sqrt ( 9 / 9 + 16 / 9 )
sin ( theta ) = + OR  1 / sqrt ( 25 / 9 )
sin ( theta ) = + OR  1 / ( 5 / 3 )
sin ( theta ) = + OR  3 / 5
cos ( theta ) = + OR  cot ( theta ) / sqrt [ 1 + cot ( teta ) ^ 2 ]
In this case :
cos ( theta ) = + OR  ( 4 / 3 ) / sqrt [ 1 + ( 4 / 3 ) ^ 2 ]
cos ( theta ) = + OR  ( 4 / 3 ) / sqrt ( 1 + 16 / 9 )
cos ( theta ) = + OR  ( 4 / 3 ) / sqrt ( 9 / 9 + 16 / 9 )
cos ( theta ) = + OR  ( 4 / 3 ) / sqrt ( 25 / 9 )
cos ( theta ) = + OR  ( 4 / 3 ) / ( 5 / 3 )
cos ( theta ) = + OR  ( 4 * 3 ) / ( 3 * 5 )
cos ( theta ) = + OR  4 / 5
cot ( theta ) = cos ( theta ) / sin ( theta )
In quadran I cosine and sine are positive so quotient of cosine and sine will be positive.
In quadran III cosine and sine are negative so quotient of cosine and sine will be positive.
Now you have 2 sets of solutions :
1. In your equation put :
sin ( theta ) = 3 / 5
cos ( theta ) = 4 / 5
2. In your equation put :
sin ( theta ) =  3 / 5
cos ( theta ) =  4 / 5
If your e3xpression mean :
5 cos ( theta )  2 sin ( theta ) / [ 5 cos ( theta ) ] + 3 sin ( theta )
Solutions will bee :
 61 / 10
and
11 / 2