6g of metal M react completely with 23.66g of chlorine to form 29.66g of the metallic chloride. Find the empirical formula of the metallic chloride. (M = 27, Cl = 35.5)
6/27=0.2 23.66/35.
5=0.6
0.2/0.2=1 0.6/0.2=3
M1CL3
Divide by their relative atomic mass
6/27=0.222
23.66/35.5=0.666
Divide by the smallest ratio
0.222/0.222 =1
0.666/0.222=3
MCl3
M=6/27 Cl=23.66/35.5
M=0.2 Cl=0.6
Divide by the smallest number
M=0.2/0.2 Cl=0.6/0.2
M=1 Cl=3
Empirical formula=MCl3
6g/M27 23.66/35.5 = 0.6 0.2/0.2=1 0.6/0.2 = 3 EMPIRICAL FORMULAR = M1CL3 CHILEZ
Convert grams to mols.
6/27 = ?
23.66/35.5 = ?
Now find the ratio of M to Cl. The easy way to do that (if the answer isn't obvious at this point) is to divide the smaller number by itself, then divide the other number by the same small number.
M C
23.66 6
divide R.A.M by the atomic number
23.66/35.5 6/27
=0.22 =0.66
divide both side by the smallest
0.22/0.22 0.66/0.22
=1 =3
Emperical formular = MCl3