Statistics
posted by Me .
A simple random sample of cars in a city was categorized according to fuel type and place of manufacture.
domestic foreign
gasoline 146 191
diesel 18 26
hybrid 51 79
Are place of manufacture and fuel type independent?
If the two variables were independent, the chance that a sampled car is a domestic gasoline fueled car would be estimated to be about
0.0362 0.0499 0.2775 0.3820 0.5
If the two variables were independent, the expected number of foreign gas/electric hybrids would be estimated to be _______. (Please keep at least two decimal places)
Degrees of freedom =
1 2 3 4
The chisquare statistic is 0.6716. The test therefore concludes that the two variables are
independent
not independent

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Ok.. so I have done this.. And I´ve got the first questions right.. Made a fool of myself with the degrees of freedom, but now I know better... For the question of foreign/hybrid I got 195.209392 for my first try and got it wrong... I messed up the columns.. I need to pass this test.. please help me out...
Also, I get a 90% percent in the chitest for independence, so my NULL is looking good, is that correct?? 
I get 75. something for foreign and hybrid.. is that right?? And ok for NULL, meaning INDEPENDENT.. Can you help me with this?

The chisquare statistic is 0.6716. The test therefore concludes that the two variables are
independent
Degrees of freedom =
2 
So, is 75.3033 ok for Foreign and Hybrid??

I believe it is!!!!!

Exercise set 5 answers:
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what's the answer?
If the two variables were independent, the chance that a sampled car is a domestic gasoline fueled car would be estimated to be about
0.0362 0.0499 0.2775 0.3820 0.5 
and what's the answer ?
If the two variables were independent, the expected number of foreign gas/electric hybrids would be estimated to be _______. (Please keep at least two decimal places) 
75.3033 is the answer

If the two variables were independent, the chance that a sampled car is a domestic gasoline fueled car would be estimated to be about
0.0362 0.0499 0.2775 0.3820 0.5 
0.2775

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