Calculus
posted by Anonymous
Find the point on the line 3x+5y5=0 which is closest to the point (4,0). Please Help!

Steve
the slope of the given line is 3/5.
So, you want a perpendicular line through (4,0). That line will be
y = 5/3 (x+4)
The two lines intersect at (115/34,35/34)
Now just find the distance between those two points
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