physics

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a man stand on the top of the building 490 m above the ground.he throws a stone horizontally with speed15 m/s.find the time taken by the stone to reach the ground &the speed with which it hits the ground

  • physics -

    h=gt²/2
    t=sqrt(2h/g)
    v(y) = gt
    v(x) =15 m/s
    v= sqrt{v(x)²+v(y)²}

  • physics -

    A ball is thrown vertically upward with an
    initial speed of 28 m/s. Then, 1.7 s later, a
    stone is thrown straight up (from the same
    initial height as the ball) with an initial speed
    of 33.3 m/s.
    How far above the release point will the ball
    and stone pass each other? The acceleration
    of gravity is 9.8 m/s^2
    Answer in units of m

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