Math, Geometry
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A square and an equilateral triangle have equal perimeters. The area of the triangle is 2\sqrt {3} square inches. What is the number of inches in the length of the diagonal of the square?
Please give me a full clear explanation with the answer. Thanks!!!!!!!

the triangle of side s has altitude s√3/2
So, it has area 1/2 (s)(s√3/2) = s^2√3/4
So, if s^2√3/4 = 2√3,
s = √8
So, the triangle has perimeter 3√8
If the square has perimeter 3√8, it has side 3√8/4 = 3/2 √2
The diagonal of a square has length s√2, so in this case, the diagonal is 3. 
Let the side of the equilateral triangle be x
area of equilateral triangle = (1/2)x^2 sin60°
= (1/2)x^2 (√3/2) = (√3/4)x^2
(√3/2)x^2 = 2/√3
3x^2 = 4
x = 2/√3
perimeter of triangle = 3x = 6/√3
which is equal to the perimeter of the square, so each side of the square is 6/(4√3) = 3/(2√3)
let the diagonal be d
d^2 = (3/(2√3) )^2 + (3/(2√3) )^2
= 9/12 +9/12 = 18/12 = 6/4
d = √6/√4 = √6/2 
made a silly error ...
(√3/2)x^2 = 2/√3
3x^2 = 4
x^2 = 8/3
x = √8/√3
I also read your area of the triangle as 2/√3
whereas Steve took it as 2√3 
That's what happens when T_{E}X gets mixed in with text!
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