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what is the concentration of Fe3+ and I- afforded by dissolving 0.200 mol of iron (iii) iodide in a 725mL water beaker

  • chemistry -

    0.200 mol FeI3.
    M Fe = mols/L = 0.200/0.725 = ?
    M I = 3*0.200/0.725 = ?

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