math
posted by vincent .
The base of an isosceles triangle is four less than the sum of the lengths of the legs. If the perimeter of the triangle is 44, find the length of the three sides of the triangle.[ Only an algebraic solution will be accepted ]

let each of the equal sides be
let the base by y
then 2x + y = 44
y = 442x
So the base is 44  2x
"The base of an isosceles triangle is four less than the sum of the lengths of the legs" > 44 2x = 2x4
44  2x = 2x  4
4x = 48
x = 12
Each of the two legs is 12, and the base is 4424 = 20
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