# chemistry

posted by .

The kinetic energy of a rolling billiard ball is given by KE=1/2mv2. Suppose a 0.17-kg billiard ball is rolling down a pool table with an initial speed of 4.7m/s . As it travels, it loses some of its energy as heat. The ball slows down to 3.7m/s and then collides straight-on with a second billiard ball of equal mass. The first billiard ball completely stops and the second one rolls away with a velocity of 3.7m/s . Assume the first billiard ball is the system

Calculate W, Calculate q, Calculate ΔE .

• This is Physics -

Hopefully someone double checks what I am going to tell you, but here it goes:

Work=KE

W=∆KE=Kf-Ki= 1/2(0.17kg)(4.7m/s)-1/2(0.17)(3.7m/s)=1/2(0.17kg)[4.7m/s-3.7m/s]

heat=q=∆KE, which is lost due to the billboard rolling down the pool table. What is the difference between the KEintial and KEfinal?

∆E=q + W

I am not sure about what I have told you, but someone will check and hopefully give you the correct response if I am wrong.

• This is Physics -

Typo:

W=∆KE=Kf-Ki= 1/2(0.17kg)(3.7m/s)-1/2(0.17)(4.7m/s)=1/2(0.17kg)[3.7m/s-4.7m/s]

• This is Physics -

Work=KE

W=∆KE=Kf-Ki= 1/2(0.17kg)(0m/s)-1/2(0.17)(4.7m/s)=1/2(0.17kg)[0 m/s-4.7m/s]

**Note: Work will be negative once you calculate it.

heat=q=∆KE, which is lost due to the billboard rolling down the pool table. What is the difference between the KEintial and KE once it slows down.

q=∆KE=Kf-Ki= 1/2(0.17kg)(3.7m/s)-1/2(0.17)(4.7m/s)=1/2(0.17kg)[3.7m/s-4.7m/s]

**Note: q will also be negative, KE is lost meaning heat is loss

∆E=q + W

## Similar Questions

1. ### Chemistry

The kinetic energy of a rolling billiard ball is given by {\rm{KE}} = 1/2\,mv^2 . Suppose a 0.17-{\rm kg} billiard ball is rolling down a pool table with an initial speed of 4.5 m/s. As it travels, it loses some of its energy as heat. …
2. ### Thermochemistry

Suppose a 0.17-kg billiard ball is rolling down a pool table with an initial speed of 4.5 m/s. As it travels, it loses some of its energy as heat. The ball slows down to 3.5 m/s and then collides straight-on with a second billiard …
3. ### chemistry

The kinetic energy of a rolling billiard ball is given by {\rm{KE}} = 1/2\,mv^2 . Suppose a 0.17-{\rm kg} billiard ball is rolling down a pool table with an initial speed of 4.5 m/s. As it travels, it loses some of its energy as heat. …
4. ### physics college

A billiard ball that is initially at rest is given a sharp blow by a cue stick. The force is horizontal and is applied at a distance h = 2R/3 below the centerline, as shown in the figure below. The speed of the ball just after the …
5. ### chemistry

Are my answers correct? Identify each energy exchange as primarily heat or work and determine weather the sign of ΔE is positive or negative for the system. A. A rolling billiard ball collides with another billiard ball. The first
6. ### chemistry

Are my answers correct? Identify each energy exchange as primarily heat or work and determine weather the sign of ΔE is positive or negative for the system. A. A rolling billiard ball collides with another billiard ball. The first
7. ### Chemistry

Are my answers correct? Identify each energy exchange as primarily heat or work and determine weather the sign of ?
8. ### Physics

A billiard ball traveling at 3.00 m/s collides perfectly elastically with an identical billiard ball initially at rest on the level table. The initially moving billiard ball deflects 30.0° from its original direction. What is the …
9. ### Chemistry/Physics

The kinetic energy of a rolling billiard ball is given by KE=1/2mv2. Suppose a 0.17-kg billiard ball is rolling down a pool table with an initial speed of 4.7m/s . As it travels, it loses some of its energy as heat. The ball slows …
10. ### physics

a billiard ball rolling across a table at 1.50m/s makes a head on collision with an identical ball. find the speed of each ball after the collision;when the ball is at rest;when the 2nd ball ]is moving towards the first at the speed …

More Similar Questions