Math
posted by Denise .
Use the elimination method to solve the system of equations
5u+2v=15
3u+v=7

1st one: 5u + 2v = 15
double the 2nd: 6u + 2v = 14
subtract them:
u = 29
u = 29
sub into 2nd:
3(29) + v = 7
v= 7 + 87 = 80
u = 29 , v = 80
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