STATISTICS

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From a group of 12 people, you randomly select 3 of them. Find the probability that at least one of them is among the 3 oldest people in the group

  • STATISTICS -

    There are 12C3 = 220 ways, group of 3 people from 12
    There are 9C3 = 84 ways, none of the three oldest.

    220-84 = 136 groups where at least one member is 3 oldest.

    136/220 = 0..618

  • STATISTICS -

    Alternatively: It's the complement of the probability that none of them is among that group.

    Let E[n] be the indexed event that the [n]th person selected is not one of the three oldest.

    1 - P(E1) P(E2|E1) P(E3|E1 and E2)
    = 1 - (9/12) (8/11) (7/10)
    = 0.61818....

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