Math
posted by Emma .
Determine the ycoordinate of the local minimum on the graph of the function f(x) = x5  6x2 + x + 4.

f(x) = x^5  6x^2 + x + 4
f '(x) = 5x^4  12x + 1
= 0 for a max/min
Not an easy equation to solve,
Wolfram shows two real solutions,
x = appr 1.3098 or x = appr .08335
http://www.wolframalpha.com/input/?i=5x%5E4++12x+%2B+1+%3D+0
f(1.3098) = 1.129
f(.08335) = 4.04167
so the y of the local min is appr 1.129
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