Name the slope and a point on
Y-3= -2(x=5)than graph the line
y-3 = -2(x+5)
y = -2x - 7
now it's in slope-intercept form.
pick any value for x (0 is easy) and calculate y for a point on the line.
(-5,3)
(-2,3)
To find the slope and a point on the line represented by the equation y - 3 = -2(x - 5), we can start by rewriting the equation in slope-intercept form, which is y = mx + b, where m represents the slope and b represents the y-intercept.
Let's rewrite the equation:
y - 3 = -2(x - 5)
Distribute the -2:
y - 3 = -2x + 10
Add 3 to both sides to isolate y:
y = -2x + 13
Now we can identify the slope and a point on the line:
The slope (m) is the coefficient of x in the equation, which is -2.
A point on the line can be any coordinate on the line. To find a point, let's set x = 0, substitute it into the equation and solve for y:
y = -2(0) + 13
y = 13
Therefore, a point on the line is (0, 13).
To graph the line, plot the point (0, 13), and use the slope of -2 to find additional points. Since the slope is negative, we can move down 2 units and right 1 unit to find the next point, then connect the two points to graph the line. Repeat this process to find more points if needed.