Physics
posted by Todd .
200 g of ic is at 5C is dropped into a container containing water at 65C. If the final temperature of the mixture reaches 21C, what mass of water must be present in the container?

Ice
m₁=200 g = 0.2 kg
c₁ = 2060 J/kg•K
λ =335000 J/kg
Water
c₂=4183 J/kg•K
m₂=?
m₁c₁[0(5)] + m₁λ+ m₁c₂(210) = m₂c₂(6521)
m₂=m₁(5c₁+λ+21c₂)/44 c₂ =
=0.2(5•2060 +335000+21•4183)/44•4183 =
=0.2(103000+335000+87843)/184052 =
=0.57 kg
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