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Collision derivation problem. A car is released from rest on a frictionless inclined plane. Assume h/L is approximately equal to y/x.
equations.

If the car has a mass of 0.2 kg, the ratio of height to width of the ramp is 11/110, the initial displacement is 2.25 m, and the change in momentum is 0.46 kg*m/s, how far will it coast back up the ramp before changing directions? Use equation :
change in momentum = mass [(2g(h/L)]^(1/2) [(L initial)^(1/2) + (L final)^(1/2)]

I keep plugging everything in and get 0.0196 meters, but that is the wrong answer when I type it in. Any help would be very much appreciated, thank you.

  • physics -

    I'm really confused on this problem too. Does anyone understand how to do it?????????

  • physics -

    I solved and got 0.399m and that was wrong, so I don't know...

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