Calculus
posted by Anonymous .
Find f(x) by solving the initial value problem.
f '(x) = 3ex  4x; f(0) = 10
f(x) =

f(x) = 3e^x 2x^2 + c
10 = 3e^0 2(0)^2+ c
10 =30+ c
7= c
F(x) = 3e^x 2x^2 + 7
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