Calculus
posted by Anonymous .
Find f (x) by solving the initial value problem.
f '(x) = 6x^2  10x; f(2) = 5
f(x) =

I am only going to do one of these because if you have seen one you have seen them all.
f(x) = 6 (x^3/3)  10 (x^2/2) + c
= 2 x^3  5 x^2 + c
no find c by using the one point given
5 = 2 (2)^3  5 (2)^2 + c
5 = 16  20 + c
c = 9
so
f(x) = 2 x^3  5 x^2 + 9