# Calculus

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Find f (x) by solving the initial value problem.
f '(x) = 6x^2 - 10x; f(2) = 5
f(x) =

• Calculus -

I am only going to do one of these because if you have seen one you have seen them all.

f(x) = 6 (x^3/3) - 10 (x^2/2) + c
= 2 x^3 - 5 x^2 + c

no find c by using the one point given
5 = 2 (2)^3 - 5 (2)^2 + c
5 = 16 - 20 + c
c = 9

so
f(x) = 2 x^3 - 5 x^2 + 9

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